5b^2+240=-70b

Solution for 5b^2+240=-70b equation:

5b^2+240=-70b

We move all terms to the left:

5b^2+240-(-70b)=0

We get rid of parentheses

5b^2+70b+240=0

a = 5; b = 70; c = +240;
Δ = b2-4ac
Δ = 702-4·5·240
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-10}{2*5}=\frac{-80}{10}
=-8
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+10}{2*5}=\frac{-60}{10}
=-6
$